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How to Test for Even or Odd Number in Javascript?


Even numbers are those numbers that are exactly divisible by 2.

The remainder operator % gives the remainder when used with a number. For example,

const number = 6;
const result = number % 4; // 2 

Hence, when % is used with 2, the number is even if the remainder is zero. Otherwise, the number is odd.

Using if...else


// program to check if the number is even or odd
// take input from the user
const number = prompt("Enter a number: ");

//check if the number is even
if(number % 2 == 0) {
    console.log("The number is even.");
}

// if the number is odd
else {
    console.log("The number is odd.");
}

Output

Enter a number: 27
The number is odd.

Using Ternary Operator


// program to check if the number is even or odd
// take input from the user
const number = prompt("Enter a number: ");

// ternary operator
const result = (number % 2  == 0) ? "even" : "odd";

// display the result
console.log(`The number is ${result}.`);

Output

Enter a number: 5
The number is odd.


Conclusion

In this page (written and validated by ) you learned about . What's Next? If you are interested in completing Javascript tutorial, we encourage you simply to start here: Javascript Tutorial.



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