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Javascript Comparing Strings

To compare strings alphabetically, use localeCompare(). This returns a negative value if the reference string is lexicographically (alphabetically) before the compared string (the parameter), a positive value if it comes afterwards, and a value of 0 if they are equal.


var a = "hello";
var b = "world";
console.log(a.localeCompare(b));

Output

-1

The > and < operators can also be used to compare strings lexicographically, but they cannot return a value of zero (this can be tested with the == equality operator). As a result, a form of the localeCompare() function can be written like so:


function strcmp(a, b) {
 if(a === b) {
 return 0;
 }
 if (a > b) {
 return 1;
 }
 return -1;
}
console.log(strcmp("hello", "world")); // -1
console.log(strcmp("hello", "hello")); // 0
console.log(strcmp("world", "hello")); // 1

Output

-1
0
1

This is especially useful when using a sorting function that compares based on the sign of the return value (such as sort)


var arr = ["bananas", "cranberries", "apples"];
arr.sort(function(a, b) {
 return a.localeCompare(b);
});
console.log(arr);

Output

[ "apples", "bananas", "cranberries" ]


Conclusion

In this page (written and validated by ) you learned about Javascript Comparing Strings . What's Next? If you are interested in completing Javascript tutorial, your next topic will be learning about: Javascript Escaping quotes.



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