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Open File Dialog in C#

To create an OpenFileDialog window in C# you can create a new object using OpenFileDialog() from using System.Windows.Forms; namespace, next you will check whether ShowDialog() Method is returning a DialofResult.OK property, Finally you can get the selected file using the property FileName


using System;
using System.Windows.Forms;

public class Program
	public static void Main()
		OpenFileDialog dialog = new OpenFileDialog();
		if (DialogResult.OK == dialog.ShowDialog()) 
			string path = dialog.FileName;


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