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Oracle Regular expression


Let's say we want to replace only numbers with 2 digits: regular expression will find them with (\d\d)

SELECT REGEXP_REPLACE ('2, 5, and 10 are numbers in this example', '(\d\d)', '#')
FROM dual;

Results in:

'2, 5, and # are numbers in this example'

If I want to swap parts of the text, I use \1, \2, \3 to call for the matched strings:

SELECT REGEXP_REPLACE ('swap around 10 in that one ', '(.*)(\d\d )(.*)', '\3\2\1\3')
FROM dual;

SUBSTR


SUBSTR retrieves part of a string by indicating the starting position and the number of characters to extract

SELECT SUBSTR('abcdefg',2,3) FROM DUAL;

returns:

bcd

To count from the end of the string, SUBSTR accepts a negative number as the second parameter, e.g.

SELECT SUBSTR('abcdefg',-4,2) FROM DUAL;

returns:

de

To get the last character in a string: SUBSTR(mystring,-1,1)

Conclusion

In this page (written and validated by ) you learned about Oracle Regular expression . What's Next? If you are interested in completing Oracle tutorial, your next topic will be learning about: Oracle IF THEN ELSE Statement.



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